It's a bit strong to say that C doesn't have TCO. The language doesn't *require*... | Hacker News

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stephencanon on Aug 5, 2012 | parent | context | favorite | on: NASA JPL C Coding Standard [pdf]

It's a bit strong to say that C doesn't have TCO. The language doesn't require TCO, but compilers are free to implement it (and indeed many of them do).

silentbicycle on Aug 5, 2012 [–]

But you can't depend on it. Since TCO changes the fundamental order of growth for space, it makes a huge difference.

Embedded C compilers typically do not have TCO.

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